题目内容：

化简f﹙x﹚＝2cosxsin﹙x+π／3﹚-根号3sin∧2x+sinxcosx的值

优质解答

f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx
=2cosx(√3/2sinx+1/2cosx)-√3sin^2x+1/2sin2x
=√3/2sin2x+cos^2x-√3sin^2x+1/2sin2x
=(√3+1)/2sin2x+cos^2x-√3sin^2x
=(√3+1)/2sin2x+(cos2x+1)/2+√3/2(cos2x-1)
=(√3+1)/2(sin2x+cos2x)+(√3-1)/2
=(√6+√2)/2sin(2x+π/4)+(√3-1)/2
2x+π/4=2kπ-π/2 ,x=kπ-3π/8 ,k∈Z
最小值f(kπ-3π/8)=-(√6+√2)/2+(√3-1)/2