题目内容：

在△ABC中,点M是BC的中点,点N在边AC上,且AN=2AC,AM与BN相交于P,求AP：PM的值.

优质解答

请问题目错了么?AN=2AC?AN=2NC吧PA=XAM,PB=YBN PC+CA=PA PC+CB=PB PA-CA=PB-CB XAM-CA=YBN-CB X(AB+BM)-CA=Y(BA+AN)-CB X(AC+CB+1/2BC)-CA=Y(BC+CA+2AC/3)-CB X(AC-1/2BC)+AC=Y(BC-AC/3)+BC (X+1)AC-X/2BC=-Y/3AC+(Y...