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【先化简在求值[2x(x^2y-xy^2)+xy(xy-x^2)]÷(x^2y),其中x=2008,y=2007】
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先化简在求值[2x(x^2y-xy^2)+xy(xy-x^2)]÷(x^2y),其中x=2008,y=2007优质解答
[2x(x^2y-xy^2)+xy(xy-x^2)]÷(x^2y)=[2x*xy(x-y)+xy*x(y-x)]÷(x^2y)=[2x^2*y(x-y)-x^2*y(x-y)]÷(x^2y)=x^2*y(x-y)÷(x^2y)=x-y把x=2008,y=2007代入上式,得[2x(x^2y-xy^2)+xy(xy-x^2)]÷(x^2y)=x-y=2008-2007=...
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