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整式的除法.我马上就要去补课了.1.[(x-1)(x+2)+2]÷x2.(6an+2的次方-9an+1次方+3an-1次
题目内容:
整式的除法.我马上就要去补课了.
1.[(x-1)(x+2)+2]÷x
2.(6an+2的次方-9an+1次方+3an-1次方)÷3an-1次方
3.(x²-2xy)·9x²-(9xy三次方-12x四次方y²)÷3xy
4.[(x+y)(x-y)-(x-y)²+2y(x-y)]÷4y优质解答
1.原式=(x^2+2x-x-2+2)÷x=x+1
2.原式=(6^an+2-9an+1)÷3^an-1
=(2^an+2)x3^(an+2-an+1)-3^2(an+1)÷3^an-1
=3^3(2^an+3)-3^(2an+2-an+1)
=3^3(2^an+2)-3^(an+3)+1
3.原式=9x^4-18x^3y-(3y^2-4x^3y)
=9x^4-14x^3y-3y^2
4.原式=[x^2-y^2-(x^2-2xy+y^2)+2xy-2y^2]÷4y
=(x^2-y^2-x^2+2xy-y^2+2xy-2y^2)÷4y
=(4xy-4y^2)÷4y
=x-y
1.[(x-1)(x+2)+2]÷x
2.(6an+2的次方-9an+1次方+3an-1次方)÷3an-1次方
3.(x²-2xy)·9x²-(9xy三次方-12x四次方y²)÷3xy
4.[(x+y)(x-y)-(x-y)²+2y(x-y)]÷4y
优质解答
2.原式=(6^an+2-9an+1)÷3^an-1
=(2^an+2)x3^(an+2-an+1)-3^2(an+1)÷3^an-1
=3^3(2^an+3)-3^(2an+2-an+1)
=3^3(2^an+2)-3^(an+3)+1
3.原式=9x^4-18x^3y-(3y^2-4x^3y)
=9x^4-14x^3y-3y^2
4.原式=[x^2-y^2-(x^2-2xy+y^2)+2xy-2y^2]÷4y
=(x^2-y^2-x^2+2xy-y^2+2xy-2y^2)÷4y
=(4xy-4y^2)÷4y
=x-y
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