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设a=(根号5-1)/2则(a^5+a^4-2a^3-a^2-a+2)/(a^3-a)会等于?
题目内容:
设a=(根号5-1)/2 则(a^5 + a^4 - 2a^3 - a^2 -a +2)/(a^3 - a ) 会等于?优质解答
a=(√5-1)/2,则a+1=(√5+1)/2,所以 a(a+1)=1
(a^5 + a^4 - 2a^3 - a^2 -a +2)/(a^3 - a )
=〔a^3(a+2)(a-1)-(a+2)(a-1)]/[(a(a+1)(a-1)]
=[(a+2)(a-1)(a^2+a+1)]/[a(a+1)]
=(√5+3)/2*(√5-3)/2*[a(a+1)+1]
=-1*2
=-2
优质解答
(a^5 + a^4 - 2a^3 - a^2 -a +2)/(a^3 - a )
=〔a^3(a+2)(a-1)-(a+2)(a-1)]/[(a(a+1)(a-1)]
=[(a+2)(a-1)(a^2+a+1)]/[a(a+1)]
=(√5+3)/2*(√5-3)/2*[a(a+1)+1]
=-1*2
=-2
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