数列{an}中,已知a2=3,a7=15,且知其通项公式是关于项数n的一次函数.(1)求此数列的通项公式;(2)将此数列中的偶数项全部取出并按原来的先后顺序组成一个新的数列{bn},求数列{bn}的通项公式
https://www.ouer.net/chuzhongshuxue/02c4.html - 2022-11-21 17:36:25 - 中学数学试题等比数列{an}中,a1=2,a4=16.(Ⅰ)求数列{an}的通项公式;(Ⅱ)若a3,a5分别为等差数列{bn}的第4项和第16项,试求数列{bn}的前项和Sn..(Ⅰ)设{an}的公比为q,由已知得
https://www.ouer.net/chuzhongshuxue/k46x.html - 2022-07-23 12:57:05 - 中学数学试题数列{an}的前N项和为Sn,a1=1,an+1=2Sn(n∈N*).(Ⅰ)求数列{an}的通项an;(Ⅱ)求数列{nan}的前n项和Tn..
https://www.ouer.net/shuxue/1f4v.html - 2020-10-26 19:40:27 - 数学作业答案兔子数列是什么意思.兔子数列,也就是著名的斐波纳契数列(Fibonacci Sequence),又称黄金分割数列.在数学上,斐波纳契数列以如下被以递归的方法定义:F0=0,F1=1,Fn=F(n-1)+
https://www.ouer.net/zati/h43b.html - 2022-06-14 12:56:16 - 中学考试杂题【急】已知数列an满足1/a1a2+1/a2a3+……1/an-1an=(n-1)/a1an,求证为等差数列已知数列an满足1/(a1a2)+1/(a2a3)+……1/(an-1an)=(n-1)/a1an
https://www.ouer.net/chuzhongshuxue/fmks.html - 2022-09-25 07:16:29 - 中学数学试题观察数列,将数列补充完整:1,3,8,22,60,( ),48..
https://www.ouer.net/shuxue/n22mw.html - 2021-09-11 06:01:39 - 数学作业答案已知递增的等比数列{an},前三项之积为512,且这三项分别减去1,3,9后又成等差数列,求数列{an}的通项公式..设等比数列{an}的公比为q,∵等比数列{an}的前三项之积为512,∴a1a2a3
https://www.ouer.net/chuzhongshuxue/xchb.html - 2022-11-11 17:06:12 - 中学数学试题在等比数列{an}中,已知a1=1,ak=243,q=3,则数列{an}的前k项的和Sk=______..等比数列前n项和为sn=a1−anq1−q,∵等比数列{an}中,已知a1=1,ak=243,q
https://www.ouer.net/chuzhongshuxue/wva4.html - 2022-11-05 08:43:09 - 中学数学试题数列{an}中,前n项和Sn=3∧n+1⑴求a1⑵求通项公式an⑶该数列是等比数列吗.1.a1=s1 =3的1次方+1 =42.这种题可以用“再写一遍法”Sn=3的n次方+1S(n+1)=3的(n+1)
https://www.ouer.net/chuzhongshuxue/emn.html - 2022-02-23 09:34:21 - 中学数学试题一个等差数列与一个等比数列相乘的问题(数学)如题,比如:等差数列an=n,等比数列bn=2^n,求cn=an*bn的前n项和Tn.这类求和怎么解决?.
https://www.ouer.net/chuzhongshuxue/c554.html - 2022-10-01 04:01:50 - 中学数学试题设等差数列a的前n项和为Sn,等比数列(Bn)的前n项和为Tn(q大於0),知道等差数列首项为1,等比数列首项为3,A3+b3=17,Tn-S3=12.求等差和等比的通项公式.
https://www.ouer.net/shuxue/sd3b.html - 2020-11-28 14:26:33 - 数学作业答案3,3,4,6,9,13.数列这个数列是个什么规律.3+0=33+1=4 4+2=6 6+3=9 9+4=13 13+5=18 加数递增1
https://www.ouer.net/chuzhongshuxue/xsra.html - 2022-11-12 07:30:27 - 中学数学试题在公差不为0的等差数列{an}与等比数列{bn}中,设a1=1,b1=1,a2=b2,a8=b3.1求数列{an}的公差和数列{bn}的公比2,求数列{bn}的前n项和3,是否存在常数a,b属于R使得对一切正整数
https://www.ouer.net/chuzhongshuxue/vrux.html - 2022-10-27 19:03:14 - 中学数学试题设a1,a2,…,an是各项不为零的n(n≥4)项等差数列,且公差d≠0.若将此数列删去某一项后,得到的数列(按原来顺序)是等比数列,则所有数对(n,a1d)所组成的集合为______..设数列{an}
https://www.ouer.net/chuzhongshuxue/duh2.html - 2022-08-16 22:25:20 - 中学数学试题[中学联盟]江苏省连云港市岗埠中学2017届九年级3月月考数学试卷我们把按照一定顺序排列的一列数称为数列,如1,3,9,19,33,就是一个数列,如果一个数列从第二个数起,每一个数与它前一个数的差等于同一个常数
https://www.ouer.net/chuzhongshuxue/nzuwf.html - 2023-03-03 20:21:12 - 中学数学试题已知数列 an 满足a1=1,an+1(1为下标)=3an+4求数列an的通项公式.
https://www.ouer.net/chuzhongshuxue/wk5w.html - 2022-11-03 08:22:19 - 中学数学试题若数列{an} a2=2 a6=0 且{1/(an+1)}是等差数列,则a4=多少.数列{1/an+1}是等差数列 1/(a4+1)-1/(a2+1)=1/(a6+1)-1/(a4+1) 2/(a4+1
https://www.ouer.net/chuzhongshuxue/vws3.html - 2022-10-28 20:57:53 - 中学数学试题设{an}是一个公差为2的等差数列,a1,a2,a4,成等比数列.求数列{an}的通项公式an..a1 = a2 -2 ,a4 = a2 +4所以,(a2 -2 )(a2 +4)=(a2)²所以
https://www.ouer.net/chuzhongshuxue/brb3.html - 2022-09-13 09:05:19 - 中学数学试题己知{an}为等差数列,a1=2,a2=3,若在每相邻两项之间插入三个数,使它和原数列的数构成一个新的等差数列,求:(1)原数列的第12项是新数列的第几项?(2)新数列的第29项是原数列的第几项?.
https://www.ouer.net/chuzhongshuxue/s86u.html - 2022-10-16 18:24:44 - 中学数学试题请问等差数列的前N项和有什么性质 等比数列呢?.等差S(2n-1)=(2n-1)an sn s2n-sn s3n-s2n 成等差数列sn-s(n-1)=an
https://www.ouer.net/chuzhongshuxue/sf20.html - 2022-10-12 08:15:49 - 中学数学试题设Sn是等差数列{an}的前n项和,a12=-8,S9=-9,证明数列{Sn/n}是等差数列.a12=a1+11d=-8 s9=(a1+a9)*9/2=9a1+36d=-9所以 a1=3 d=-1sn/
https://www.ouer.net/chuzhongshuxue/xv21.html - 2022-11-12 22:36:14 - 中学数学试题已知数列{an}的前n项和为Sn,Sn=(an-1)/3 (n∈N)(1)求a1,a2(2)求证数列{an}是等比数列.n=1,S1=a1=(a1-1)/3,a1=-1/2;n=2,S2=a1+a2=(
https://www.ouer.net/chuzhongshuxue/b22m.html - 2022-09-15 15:57:23 - 中学数学试题求数列通项1.已知数列{an}满足:a(n+1)方=an方+4且a1=1,an>0,求an2.在数列{an}中,a1=2,a(n+1)=an+3n+2,求an3.已知a1=1,a(n+1)-an=2的n
https://www.ouer.net/chuzhongshuxue/cm6s.html - 2022-10-02 20:18:54 - 中学数学试题数列{an}=n,若数列{cn}满足a1c1+a2c2+.+ancn=n(n+1)(n+2)q求数列前n项和Wn.1,a1c1+a2c2+.
https://www.ouer.net/chuzhongshuxue/rs1k.html - 2022-10-05 19:40:36 - 中学数学试题已知数列{an}为等差数列,Sn为其前n项和,且a1=10,s12=-125求数列{an}的通项公式an.设an=a1+(n-1)d=10+(n-1)dSn=na1+(n-1)nd/2=10n+(n-1
https://www.ouer.net/chuzhongshuxue/e8h.html - 2022-02-23 06:07:07 - 中学数学试题已知数列{an}为等差数列,其前n项和为Sn,且a5=8,S5=20 (1)求Sn;(2)若...已知数列{an}为等差数列,其前n项和为Sn,且a5=8,S5=20 (1)求Sn;(2)若对任意n>t
https://www.ouer.net/chuzhongshuxue/mna.html - 2022-02-23 11:53:17 - 中学数学试题等差数列{An}是公差不为0的等差数列,且第7项,第10项,第15项,是等比数列{Bn}的连续三项,B1=3,求Bn=___.
https://www.ouer.net/shuxue/nb32k.html - 2020-11-26 13:54:21 - 数学作业答案已知数列an,bn为等差数列,An,Bn表示数列an,bn的前n项和,若a1=60,b1=40,A100+B100=0,求a100+b100.a100+b100=-100
https://www.ouer.net/zati/ka4v.html - 2022-06-27 07:59:29 - 中学考试杂题(实分析,数列,极限)当n趋近无穷时,数列Sn/n=非零常数C,求证:数列Sn发散向无穷实数方程f 在R上一致连续,若定义fn(x)=f(x+1/n),求证:数列fn一直连续并趋向f.求证:不存在连续方程
https://www.ouer.net/chuzhongshuxue/bw85.html - 2022-09-14 15:16:30 - 中学数学试题已知数列an是等差数列,且a1=2,a1+a2+a3=12.令bn=an*x^n(x属于R),求数列bn前n项和的公式..因为是等差数列,所以a1+a2+a3=3a2=12,a2=4,d=a2-a1=2
https://www.ouer.net/zati/b6c.html - 2022-01-28 23:40:14 - 中学考试杂题已知函数f(x)=2^x-2^-x,数列{an}满足f(log2an)=-2n(1)求数列{an}的通项公式 (2)求数列{an}中的最大的项..f(log2an)=2^(log2an)-2^(-log2an
https://www.ouer.net/chuzhongshuxue/mzh.html - 2022-02-23 13:09:23 - 中学数学试题已知数列{an}是各项均不为0的等差数列,公差为d,Sn为其前n项和,且满足an^2=S2n-1,n∈N*,数列{bn}满足bn=1/(an·an+1),Tn为数列{bn}的前n项和.(1)求a1、d、
https://www.ouer.net/chuzhongshuxue/fmb4.html - 2022-09-25 07:51:51 - 中学数学试题一道高三数列题哦已知数列{an}满足2^nan=2^(n-1)a(n+1)+ana(n+1)且a1=1,求数列{an}的通项公式.等式两边同除以a(n)a(n+1)得2^n/a(n+1)-2^(n-1)
https://www.ouer.net/chuzhongshuxue/s4sn.html - 2022-10-15 13:35:50 - 中学数学试题设数列{an}的前n项和为Sn=2n^2,{bn}为等比数列,且a1=b1,b2(a2-a1)=b1.(1)求数列{an}和{bn}的通项公式;(2)设Cn=an/bn,求数列{Cn}的前n项和Tn..
https://www.ouer.net/shuxue/1f28.html - 2020-12-30 17:57:14 - 数学作业答案数列{An},{Bn},已知An=nlg3-(n+1)lg2,Bn=A3n,试问数列{Bn}是等差数列吗?如果不是请说明理由,如果是请证明?.
https://www.ouer.net/chuzhongshuxue/x6wu.html - 2022-11-15 09:11:19 - 中学数学试题已知公差不为零的等差数列{an}与等比数列{bn}中,b1=a2=1,b2=a3,b3=a6 (1)求数列{an}{bn}通项公式(2)设cn=[(an +1)λ ^n]/2 +2^n(λ ≠0),求数列
https://www.ouer.net/chuzhongshuxue/w74w.html - 2022-11-08 07:19:06 - 中学数学试题等差数列{an}满足a2=0,a6+a8=-10 (Ⅰ)求数列An的通项公式 (Ⅱ)求数列{An/2的n-1次幂)的前n项和.
https://www.ouer.net/shuxue/1f35.html - 2021-05-12 16:59:08 - 数学作业答案已知数列根号3,根号7,根号11,根号15则5根号3是数列的.
https://www.ouer.net/shuxue/1sz5.html - 2021-05-12 22:04:51 - 数学作业答案数列{an}是等差数列,且an=an^2+n则实数a=要过程.当n≥1时,an=an²+n,则:a(n-1)=a(n-1)²+(n-1)d=an-a(n-1)=[an²+n
https://www.ouer.net/chuzhongshuxue/reb5.html - 2022-10-09 19:02:43 - 中学数学试题摆动数列有极限么?有界么?.摆动数列是指即增又减得数列,就是一会增一会减即上下摆动,因此摆动数列一般是没有规律的,不具备规律的数列不一定是摆动数列,摆动数列也不一定是没有规律的数列!
https://www.ouer.net/chuzhongshuxue/feu3.html - 2022-09-25 02:30:28 - 中学数学试题数列 (4 15:51:13)已知等差数列{an}和等比数列{bn}中,a1=0,公差d≠0,且a1+b1=1,a2+b2=1,a3+b3=2,求这两个数列的通项公式..因为a1=0,所以b1=1,所以
https://www.ouer.net/chuzhongshuxue/vrbe.html - 2022-10-27 17:57:14 - 中学数学试题设数列{an}是首项为a1(a1>0),公差为2的等差数列,其前n项和为Sn,且根号S1,S2,S3成等差数列.求数列{an}的通项公式.
https://www.ouer.net/shuxue/e08b.html - 2020-11-17 15:50:00 - 数学作业答案在数列{An}中,An小于0(n属于正整数),数列{AnAn+1}是公比为q的等比数列,且满足2AnAn+1+An+1An+2>An+2An+3,则公比Q的取值范围?.
https://www.ouer.net/shuxue/s5nx.html - 2020-12-24 02:53:49 - 数学作业答案在等比数列{an}中,an>0,且an+2=an+an+1,则该数列的公比q=______..
https://www.ouer.net/chuzhongshuxue/02zx.html - 2022-11-21 16:04:33 - 中学数学试题1.数列{An}中A1=2,A2=-1,An^2=A(n+1)*A(n-1)(n≥2),则An=?
https://www.ouer.net/chuzhongshuxue/b22k.html - 2022-09-15 15:43:09 - 中学数学试题数列{an}中,Sn-2an=2n.(1)求证{an-2}是等比数列;(2)若an=bn+1-bn,b1=3,求数列{bn}的通项公式;(3)若cn=nbn-2n2,求数列{cn}的前n项和Tn..(1
https://www.ouer.net/chuzhongshuxue/x76f.html - 2022-11-15 18:34:57 - 中学数学试题已知数列{an}a1=2前n项和为Sn 且满足Sn Sn-1=3an 求数列{an}的通项公式an已知数列{an}a1=2前n项和为Sn 且满足Sn +Sn-1=3an 求数列{an}的通项公式an.因为
https://www.ouer.net/chuzhongshuxue/e40.html - 2022-02-23 01:59:12 - 中学数学试题不要计算错啊1.数列{an}中,a1=2,a(n+1)=2an+n^2+2n+1,求数列{an}的通项公式2.数列{an}满足a1=1,an=1/2a(n-1)+1(n≥2),求数列{an}的通项公式.1
https://www.ouer.net/zati/hc6e.html - 2022-05-28 14:28:12 - 中学考试杂题数列所有公式.1.等差数列:an=a1+(n-1)d=Sn-S(n-1)(n≥2)=kn+bSn=n(a1+an)/2=na1+n(n-1)d/2an=am+(n-m)d2.等比数列:an=a1q^(n
https://www.ouer.net/chuzhongshuxue/hrfr.html - 2022-05-28 06:07:06 - 中学数学试题关于数学数列习题提问1 设an是等差数列,bn是各项都为正数的等比数列且a1=b1=1,a3+a5=21,a5+b3=13 求an与bn的通项公式2已知数列an为等差数列,公差d不等于0,其中ak1(k1
https://www.ouer.net/chuzhongshuxue/rnhz.html - 2022-10-03 04:57:46 - 中学数学试题