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matlab 解三角函数方程弧度与角度问题[theta11,theta12,theta13]=solve('(94*co
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matlab 解三角函数方程弧度与角度问题
[theta11,theta12,theta13]=solve('(94*cosd(theta13))/5-10*sind(theta11)*sind(theta13)-(79*cosd(theta11)*sind(theta12)*sind(theta13))/2 - (59*cosd(theta12)*sind(theta11)*sind(theta13))/2=29.4281',' (59*sind(theta11)*sind(theta12))/2 - (79*cosd(theta11)*cosd(theta12))/2=10.1192','-(94*sind(theta13))/5 - 10*cosd(theta13)*sind(theta11) - (79*cosd(theta11)*cosd(theta13)*sind(theta12))/2 - (59*cosd(theta12)*cosd(theta13)*sind(theta11))/2=30.8552');
这个三元一次方程,用cosd等表示就不对呢?
matlab 解三角函数方程弧度与角度问题
[theta11,theta12,theta13]=solve('(94*cosd(theta13))/5-10*sind(theta11)*sind(theta13)-(79*cosd(theta11)*sind(theta12)*sind(theta13))/2 - (59*cosd(theta12)*sind(theta11)*sind(theta13))/2=29.4281',' (59*sind(theta11)*sind(theta12))/2 - (79*cosd(theta11)*cosd(theta12))/2=10.1192','-(94*sind(theta13))/5 - 10*cosd(theta13)*sind(theta11) - (79*cosd(theta11)*cosd(theta13)*sind(theta12))/2 - (59*cosd(theta12)*cosd(theta13)*sind(theta11))/2=30.8552');
这个三元一次方程,用cosd等表示就不对呢?
[theta11,theta12,theta13]=solve('(94*cosd(theta13))/5-10*sind(theta11)*sind(theta13)-(79*cosd(theta11)*sind(theta12)*sind(theta13))/2 - (59*cosd(theta12)*sind(theta11)*sind(theta13))/2=29.4281',' (59*sind(theta11)*sind(theta12))/2 - (79*cosd(theta11)*cosd(theta12))/2=10.1192','-(94*sind(theta13))/5 - 10*cosd(theta13)*sind(theta11) - (79*cosd(theta11)*cosd(theta13)*sind(theta12))/2 - (59*cosd(theta12)*cosd(theta13)*sind(theta11))/2=30.8552');
这个三元一次方程,用cosd等表示就不对呢?
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