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对于数列{xn}满足x1=a(a>2),xn+1=(n=1,2,…). (1)求证:2<xn+1<xn(n=1,2,3,…); (2)若a≤3,{xn}前n项和为Sn,求证:Sn<2n+(n=1,2,...

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