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F-(M+m)g=(M+m)a ····················☆2f-Mg=Ma···············
题目内容:
F-(M+m)g=(M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2(m+M)〕/M
F-(M+m)g=(M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2f(m+M)〕/M优质解答
(1)得F=(M+m)(g+a)
(2)得2f=M(g+a) (g+a)=2f/M
代入得
F=2f(M+m)/M
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2(m+M)〕/M
F-(M+m)g=(M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2f(m+M)〕/M
优质解答
(2)得2f=M(g+a) (g+a)=2f/M
代入得
F=2f(M+m)/M
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