题目内容：

1.工厂生产的酒精（ρ酒精=0.38g/cm3）含水量不超过10%,最多密度为?

优质解答

依题意得：m水=10%mm酒=90%mV水=m水/ρ水=10% m/ρ水=1/10* m/ρ水V酒=m酒/ρ酒=90% m/ρ酒=9/10* m/ρ酒V=V水+V酒=1/10* m/ρ水+ 9/10* m/ρ酒 ρ=m/V=m/(V水+V酒)=m/(1/10* m/ρ水+ 9/10* m/ρ酒)=1/[(1/10)*(1/...