题目内容：

梯形ABCD,AD:BC=2:3,画对角线AC和BD相交于O点,三角形ABO的面积是6平方米,求梯形的面积

优质解答

∵AD//BC∴△AOD∽△COB,∴AD/BC=OD/BO=AO/CO=2/3,S△AOD/S△COB=（AD/BC）^2=(2/3)^2=4/9∵△AOD和△AOB同高,S△COD=(3/2)S△AOD=6m^2,∴S△AOD/S△AOB=OD/OB=2/3,S△AOD=2S△AOB/3=4m^2,∴S△COB=(9/4)*4=9m^2,S△...