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已知点M0(x0,y0)和圆(x-a)^2+(y-b)^2=r^2,则点M0(x0,y0)在圆内 等价于 点M0(x0,
题目内容:
已知点M0(x0,y0)和圆(x-a)^2+(y-b)^2=r^2,则
点M0(x0,y0)在圆内 等价于______________________________
点M0(x0,y0)在圆上 等价于 _____________________________
点M0(x0,y0)在圆外 等价于 ______________________________优质解答
点M0(x0,y0)在圆内 等价于(x0-a)^2+(y0-b)^2<r^2,
点M0(x0,y0)在圆上 等价于(x0-a)^2+(y0-b)^2=r^2,
点M0(x0,y0)在圆外 等价于(x0-a)^2+(y0-b)^2>r^2,
点M0(x0,y0)在圆内 等价于______________________________
点M0(x0,y0)在圆上 等价于 _____________________________
点M0(x0,y0)在圆外 等价于 ______________________________
优质解答
点M0(x0,y0)在圆上 等价于(x0-a)^2+(y0-b)^2=r^2,
点M0(x0,y0)在圆外 等价于(x0-a)^2+(y0-b)^2>r^2,
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