题目内容：

数学好点的进来帮忙坐下这个题,
d(x+(1+x^2)^1/2)

优质解答

d(x + (1+x^2)^1/2)
=d x +d (1+x^2)^1/2
=1 + 1/{2 (1+x^2)^1/2} * d(1+x^2)
= 1 + 2x/{2 (1+x^2)^1/2}
=1 + x (1+x^2)^1/2 / (1+x^2)