题目内容：

已知a=根号2+1,b=根号2-1,求根号ab*(根号b分之a-根号a分之b)的值

优质解答

a=根号2+1,b=根号2-1
ab=1
根号ab*(根号b分之a-根号a分之b)
=根号b分之a-根号a分之b
=(a-b)/根号ab
=a-b
=根号2+1-(根号2-1)
=2