题目内容：

因式分解(x-1)的三次方+(x-2)的三次方+(3-2x)的三次方
拜托拜托 快啊 不然明天我就要被老师罚向数学课代表敬礼啦 好的我加悬赏 要详解过程!
谢谢了!

优质解答

(x-1)^3+(x-2)^3+(3-2x)^3=(x-1＋x-2)[(X-1)^2-(X-1)(X-2)+(X-2)^2]+(3-2x)^3
=(2X-3)[(X-1)^2-(X-1)(X-2)+(X-2)^2-(3-2X)^2]=(2X-3)[(X-1)^2-(X-1)(X-2)+(1-X)(3X-5)]
=(2X-3)(X-1)[(X-1)-(X-2)-(3X-5)]
=(2X-3)(X-1)(6-3X)
=-3(2X-3)(X-1)(X-2)