题目内容：

圆中,弦长6米,求半径及弧长,
RT

优质解答

弦长L=6米,拱高H=2米,求半径R及弧长C?
R=(L^2+4*H^2)/(8*H)
=(6^2+4*2^2)/(8*2)
=(36+16)/16
=52/16
=3.25米
圆心角A=2*ARC SIN(L/(2*R))
=2*ARC SIN(6/(2*3.25))
=2*ARC SIN(0.92308)
=67.38度
=67.38*PI/180
=1.176弧度
C=A*R
=1.176*3.25
=3.822米
半径为3.25米,弧长为3.822米.