题目内容：

AP、BP分别平分角CAD的补角角CAM、角CBD,请直接写出角P与角C、角D的关系,不必说明理由
我图画弄不出来,

优质解答

∠P=180-∠PBE-∠PEB
=180-1/2(180-∠C-∠CGB)-∠AED
=90+1/2∠C+1/2∠CGB-(180-∠D-∠DAE)
=1/2∠C+1/2∠CGB-90+∠D+(∠DAG+1/2∠CAM)
=1/2∠C+1/2∠CGB-90+∠D+(180-∠D-∠DGA)+1/2(∠D+∠DGA)
=90+1/2∠C+1/2∠D