题目内容：

用平方差公式解
(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)
在前面加一个（x—1）\（x—1）
怎么解,用平方差公式

优质解答

{(x-1)/(x-1)}*(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)
={(x^2-1)/(x-1)}*(x^2+1)(x^4+1)(x^8+1)(x^16+1)
={(x^4-1)/(x-1)}*(x^4+1)(x^8+1)(x^16+1)
={(x^8-1)/(x-1)}*(x^8+1)(x^16+1)
={(x^16-1)/(x-1)}*(x^16+1)
=(x^32-1)/(x-1)