题目内容：

已知ab是实数,且（根号2a+b）+ |b-根号2|=0 解关于x的方程（a+2)x+b的平方=a-1

优质解答

∵（根号2a+b）+ |b-根号2|=0∴2a+b=0 b-√2=0 a=-1/2√2 b=√2 （a+2)x+b的平方=a-1(-1/2√2+2)x+(√2)²=-1/2√2-1(-1/2√2+2)x=-1/2√2-5x=(-1/2√2-5)/(-1/2√2+2)x=(5+1/2√2)(2+1/2√2)/(2-1/2√2)(...