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求F(s)=(s-3)/(s^2-7s+6)的laplace逆变换希望能附上具体的解答过程,这laplace逆变换我不太懂,
题目内容：
求F(s)=(s-3)/(s^2-7s+6)的laplace逆变换
希望能附上具体的解答过程,这laplace逆变换我不太懂,优质解答
FactorizationF(s)=(s-3)/(s^2-7s+6)=(2/5)(1/(s-1))+(3/5)(1/(s-6))Notice that L[e^(at)]=1/(s-a)we can obtain the inverse Laplace transform of F(s) is 1/5e^t[3e^(5t)+2]
求F(s)=(s-3)/(s^2-7s+6)的laplace逆变换
希望能附上具体的解答过程,这laplace逆变换我不太懂,
希望能附上具体的解答过程,这laplace逆变换我不太懂,
优质解答
FactorizationF(s)=(s-3)/(s^2-7s+6)=(2/5)(1/(s-1))+(3/5)(1/(s-6))Notice that L[e^(at)]=1/(s-a)we can obtain the inverse Laplace transform of F(s) is 1/5e^t[3e^(5t)+2]
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