题目内容：

900ml0.05mol/l硫酸与100ml0.1mol/l的盐酸混合后pH=?

优质解答

n(H+) = 0.05*2*0.9 + 0.1*0.1 = 0.1mol
V(溶液) = 0.9+0.1 = 1L
c(H+) = 0.1/1 = 0.1mol/L
pH = -lg0.1 = 1