题目内容：

硫酸和氢氧化钠恰好完全反应,反应后溶液中溶质的质量分数为10%,此溶液中钠离子和水分子的个数比为

优质解答

设溶液的质量为ag,则：
m(Na2SO4) = 10% * ag = 0.1ag
n(Na2SO4) = 0.1ag / 142g/mol
m(H2O) = ag - 0.1ag = 0.9ag
n(H2O) = 0.9ag / 18g/mol
N(Na+) :N(H2O) = 2n(Na2SO4) :n(H2O) = ( 2* 0.1ag/142g/mol) :( 0.9ag / 18g/mol)
= 2:71