题目内容：

标况下,1体积水溶解700体积NH3,溶液密度为0.9g/cm3,求浓度
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优质解答

设水是1L,则氨气就是700L.
w =(700L/22.4L*17g)/(700L/22.4L*17g + 1L*1000g/L)*100% = 34.7%
c=(1000*0.9*34.7%)/(17*1)=18.4 mol/L