函数y=x+(1/x )的单调区间为?.答:y=x+1/xy'(x)=1-1/x^2解y'(x)=1-1/x^2=0得:x1=-1,x=1x1时,y'(x)>0,y是单调递增函数-1
https://www.ouer.net/chuzhongshuxue/ud5n.html - 2022-10-19 05:05:13 - 中学数学试题函数y=x-|1-x|的单调增区间为______..y=x-|1-x|=2x−1x≤11x>1;函数2x-1在(-∞,1]上单调递增;∴原函数的单调增区间为(-∞,1].故答案为:(-∞,1].先对原函数去绝对值
https://www.ouer.net/chuzhongshuxue/zxw1.html - 2022-04-28 18:19:10 - 中学数学试题求函数y=(13)x2−x的单调减区间为 ______..g(x)=x2-x的增区间是[12,+∞)∵函数g(x)=x2-x的增区间,就是函数的y=(13)x2−x的单调递减区间∴函数y=(13)x2
https://www.ouer.net/chuzhongshuxue/f5ea.html - 2022-09-23 21:04:58 - 中学数学试题函数y=lnx+e^x的单调递增区间为.求导,y‘=1/X+e^x因为定义域为x>0,又y'>0时,x>0 所以函数y=lnx+e^x的单调递增区间为{X|x>0}
https://www.ouer.net/zati/hx03.html - 2022-06-06 08:04:32 - 中学考试杂题如何证明函数y=1/x+x的单调增区间. 令y'=1-1/x^2>0得到:x^2-1>x>0或0单调增区间为[-1,0)及(0,1】.
https://www.ouer.net/shuxue/nnbaa.html - 2021-06-23 20:18:15 - 数学作业答案余弦函数单调区间是一定的吗.余弦函数的单调区间是分开来的,其递减区间是【2kπ,2kπ+π】其递增区间是【2kπ+π,2kπ+2π】,如果相位改变的话就按照相位的改变来改变上述区间
https://www.ouer.net/zati/kxe7.html - 2022-07-20 23:14:09 - 中学考试杂题证明函数y=x -1/x在(0,+∞)上单调递增 证明函数y=x -1/x在(0,+∞)上单调递增初学者理解下.任取(0,+∞)中的x1,x2,设x1x1>0,故x1×x2>0于是f(x2)-(x1)>
https://www.ouer.net/chuzhongshuxue/v984.html - 2022-11-01 11:33:16 - 中学数学试题对数函数单调区间求法对数函数单调区间的求法是什么?y=log1/2(-x^2-2x+3)的递减区间是什么?.y=log1/2(-x^2-2x+3)把他看成复合函数 定义域为 -3
https://www.ouer.net/chuzhongshuxue/f59d.html - 2022-09-23 20:55:42 - 中学数学试题求函数y=tan(-1/2x+/4)的单调区间求函数y=tan(-1/2x+pai/4)的单调区间,答案怎么是递减区间,那个祥细解释下!是不是tan前-所以那个才为它的减区间?.
https://www.ouer.net/chuzhongshuxue/ufz8.html - 2022-10-19 14:00:00 - 中学数学试题单调有界数列必有极限如何证明.同济课本上对这个定理的说明是:对于这个定理我们不做证明,只是给出它的在数轴上的几何意义,你可以参看一下.若要考试这个问题不会考定理证明的,而是要你先用证明某个数列的单调性,
https://www.ouer.net/zati/u9d.html - 2022-02-04 17:46:24 - 中学考试杂题y=cosx的单调递增区间是什么.方法一:对y=cosx求导y’=-sinx当y’>0时,函数递增既-sinx>0则sinx
https://www.ouer.net/chuzhongshuxue/sh9r.html - 2022-10-11 07:51:08 - 中学数学试题求函数y=tan(-x-π/6)的单调递减区间?.
https://www.ouer.net/zati/k2e2.html - 2022-07-24 23:14:06 - 中学考试杂题函数y=sin2x的单调递增区间为.因为函数y=sin2x;令 2kπ- 2π≤2x≤2kπ+ 2π⇒kπ- π≤x≤kπ +π.
https://www.ouer.net/chuzhongshuxue/d33s.html - 2022-08-26 21:35:40 - 中学数学试题求函数y=sin2x的单调递增区间.2kπ-π/2
https://www.ouer.net/chuzhongshuxue/n059.html - 2022-03-22 10:07:02 - 中学数学试题y=-x2+2x 求函数的单调增区间,并证明. -x^2-2x=-(x+1)^2+1单调增区间:xE(-oo,-1)
https://www.ouer.net/shuxue/nndmu.html - 2020-10-30 14:07:03 - 数学作业答案求函数y=-tan(2x-3π/4)的单调区间..
https://www.ouer.net/chuzhongshuxue/u1c.html - 2022-02-04 07:28:03 - 中学数学试题函数y=2^|x|的单调增区间是?.当x>0,y=2^x递增区间是:(0,正无穷)当x
https://www.ouer.net/zati/n2k3.html - 2022-03-27 11:02:07 - 中学考试杂题判断f(x)=x2-2x在(1,+∞)上的单调性..f′(x)=2x-2,∵x>1,∴2x-2>0,即f′(x)>0;∴f(x)在(1,+∞)上单调递增.求f′(x),判断f′(x)的符号,从而判断出f
https://www.ouer.net/chuzhongshuxue/3ch.html - 2022-02-13 04:24:21 - 中学数学试题求函数Y=3x²-6x的单调区间.答:y=3x²-6x=3(x²-2x+1)-3=3(x-1)²-3抛物线开口向上,对称轴x=1单调递增区间为[1,+∞)单调递减区间为
https://www.ouer.net/chuzhongshuxue/nsx5.html - 2022-03-14 00:53:05 - 中学数学试题求y=sin(π/3-x/2)在〔-2π,2π〕的单调递增区间.y=sinx的单调增区间为(-π/2+2kπ,π/2+2kπ)所以y=sin(π/3-x/2)单调增区间为-π/2+2kπ<π/3-x/2
https://www.ouer.net/chuzhongshuxue/dxf5.html - 2022-08-21 02:20:35 - 中学数学试题求函数f(x)=x2-2|x|-3的单调区间.
https://www.ouer.net/chuzhongshuxue/hdf.html - 2022-01-24 04:48:05 - 中学数学试题①求函数f(x)=log2(x²-4)的单调递减区间 ②求y=1/2的x²-2x-3次方的单调增、减区间.
https://www.ouer.net/chuzhongshuxue/dar0.html - 2022-08-02 16:26:52 - 中学数学试题函数y=x^2+4x-2的单调递增区间是______..y=x^2+4x-2=(x+2)^2-6对称轴:x=-2单调递增区间:(-∞,-2]
https://www.ouer.net/chuzhongshuxue/nx5b.html - 2022-03-19 16:22:15 - 中学数学试题怎么求y=(-3-x)/(x+2)的单调增区间..y=(-(x+2)-1)/(x+2)=-1-1/(x+2)所以,单调增区间是(-无穷,-2)和(-2,+无穷)
https://www.ouer.net/chuzhongshuxue/nx43.html - 2022-03-19 15:43:17 - 中学数学试题求sin 2x 的单调递增区间?.从(-π/4 +kπ)到(π/4 +kπ)的闭区间 注意,应注明k属于整数
https://www.ouer.net/chuzhongshuxue/zxvr.html - 2022-04-28 16:51:12 - 中学数学试题函数y= -x方+2|x|+3的单调减区间为.x
https://www.ouer.net/chuzhongshuxue/dar6.html - 2022-08-02 16:43:51 - 中学数学试题函数f(x)=x²-2ax+1的单调性如何?.开口向上,对称轴为x=a当x>=a时,单调增;当x
https://www.ouer.net/chuzhongshuxue/zxcm.html - 2022-04-28 12:53:05 - 中学数学试题关于指数函数的奇偶性和单调性(详细过程,)当a不等于1时,讨论函数f(x)=(a^x+1)/(a^x-1)的奇偶性和单调性..f(-x)=-f(x),自己化简,是奇函数,单调性讨论a是大于0小于1的还是大于
https://www.ouer.net/chuzhongshuxue/uh2.html - 2022-02-03 16:37:19 - 中学数学试题已知函数f(x)=sin2x-√3cos2x+1,x∈[π/4,π/2].求f(x)的单调区间.求出f(x)的单调增区间是[kπ-π/12,kπ+5π/12],k∈Z.求出的不是有个负数吗?
https://www.ouer.net/chuzhongshuxue/f5ex.html - 2022-09-23 21:12:43 - 中学数学试题求函数y=cos(2x+π/3),x∈[-2π,2π]的单调递增区间.y=cos(2x+π/3),x∈[-2π,2π]的单调递增区间y=cos(2x+π/3),则周期T=π设2x+π/3=X,则X∈[-
https://www.ouer.net/chuzhongshuxue/webv.html - 2022-11-08 23:41:29 - 中学数学试题函数y=-2x^2-4x+1(x∈R)的单调区间.y=-2x^2-4x+1=-2(x+1)^2 + 3开口向下,对称轴是x = -1所以在 (-∞,-1] 上单调递增在[-1,+∞)上单调递减
https://www.ouer.net/chuzhongshuxue/v181.html - 2022-10-29 19:37:56 - 中学数学试题求函数f(x)=-x2+|x|单调区间1.求函数f(x)=-x2+|x|单调区间2.已知函数f(x)=-x3+ax在(0,1)上是增函数,求a的取值.x>0f(x)=-x²+x0<x≤ 1/2
https://www.ouer.net/chuzhongshuxue/k6ed.html - 2022-07-26 09:29:15 - 中学数学试题函数y=−x2−x+2的单调递增区间为______..
https://www.ouer.net/chuzhongshuxue/d3nd.html - 2022-08-26 01:25:28 - 中学数学试题函数y=1-sin2x(x∈R)的单调递增区间.设u=sin2x,则y=1=sin2x=1-u,y是u的减函数,又因为u=six2x的单调递减区间是[π/4+kπ,3π/4+kπ],(k∈Z)所以y=1
https://www.ouer.net/chuzhongshuxue/n05e.html - 2022-03-22 10:09:07 - 中学数学试题y=sin(pi/4-2x)的单调增区间.y=sin[-(2x-π/4)]=-sin(2x-π/4)所以就是求sin(2x-π/4)的递减区间sin单调减区间是(2kπ+π/2,2kπ+3π/2)所以2kπ
https://www.ouer.net/chuzhongshuxue/dxfw.html - 2022-08-21 02:01:24 - 中学数学试题求函数y=x/1- x的单调增区间,并用定义证明.
https://www.ouer.net/shuxue/nnbad.html - 2021-06-23 20:19:15 - 数学作业答案函数y=log2(4-2x)的单调递减区间为.先求定义域4-2x大于0,x小于2因为单调减所以3/2
https://www.ouer.net/chuzhongshuxue/h40e.html - 2022-06-11 21:37:05 - 中学数学试题函数y=-e^x图像单调区间描述一下就行了,. y=-e^x的图像就是y=e^x的图像关于x轴对称,单调减区间为(-∞,+∞)
https://www.ouer.net/shuxue/nnnh7.html - 2021-06-23 06:58:20 - 数学作业答案求函数y=|x+1|的单调区间.x>-1x+1>0y=x+1此时是增函数x
https://www.ouer.net/chuzhongshuxue/r3h5.html - 2022-10-07 20:46:39 - 中学数学试题求y=log2底{4x-x平方} 的值域和单调区间.4x-x^2>0 x=2 4x-x^2->max log2(4)=2值域:[负无穷,2]单调区间:(0,4]单调增
https://www.ouer.net/chuzhongshuxue/ucb5.html - 2022-10-19 22:24:15 - 中学数学试题函数y=(x一3)x的单调递增区间.
https://www.ouer.net/zati/n2dc.html - 2022-03-27 11:48:23 - 中学考试杂题y=sin(2x+π/4)的单调递减区间.令2kπ+π/2<2x+π/4<2kπ+3π/2(k∈Z)得2kπ+π/4<2x<2kπ+5π/4(k∈Z)即kπ+π/8<x<kπ+5π/8(k∈Z)所以y=
https://www.ouer.net/chuzhongshuxue/u797.html - 2022-10-23 22:58:13 - 中学数学试题函数y=2sinx的单调减区间为.(2kπ+π/2,2kπ+3π/2),k∈Z
https://www.ouer.net/chuzhongshuxue/r6uc.html - 2022-10-08 18:06:04 - 中学数学试题利用单调有界数列收敛准则证明下列数列的极限存在.
https://www.ouer.net/shuxue/7cz.html - 2021-03-18 23:35:14 - 数学作业答案f(x)=根号下(2x^2-3x-2) 的单调减区间为?.首先要明确一个单调函数,加上根号后,在定义域内仍旧是单调性不变的单调函数. 但求解此类问题的关键是要注意定义域.
https://www.ouer.net/chuzhongshuxue/vm9.html - 2022-02-06 03:37:21 - 中学数学试题f(x)=lg(2x^2-5x-3)的单调区间RT.2x^2-5x-3>0(x-3)(2x+1)>0x>3或x3或x5/4,单调递增x3}单调递减区间{x/x
https://www.ouer.net/zati/bza.html - 2022-01-28 00:51:06 - 中学考试杂题Fx=x(e^x-1)-1/2x^2,函数的单调增区间为已知函数F(x)=x(e^x-1)-1/2x^2,求函数的单调增区间。.x=0
https://www.ouer.net/chuzhongshuxue/kdns.html - 2022-06-30 00:40:02 - 中学数学试题函数y=sin(π/3-x )的单调递减区间是.相关法sinx的单调地减去间是 [2kpi+pi/2,2kpi+3pi/2]所以pi/3-x应该属于[2kpi+pi/2,2kpi+3pi/2]2kpi+
https://www.ouer.net/chuzhongshuxue/v9u.html - 2022-02-06 00:43:05 - 中学数学试题函数二阶导数大于零单调性如何?原因!.二阶导数和单调性无关而是表示凹凸性二阶导数大于零则是凹函数,即图像是∪型的二阶导数小于零则是凸函数,即图像是∩型的
https://www.ouer.net/chuzhongshuxue/urz6.html - 2022-10-20 04:00:01 - 中学数学试题函数y=3cos(-2x+30度)+2的单调递减区间是?.
https://www.ouer.net/chuzhongshuxue/d8ww.html - 2022-09-02 06:23:25 - 中学数学试题