题目内容：

cos2B-cos2A=2sin(π/3+B)sin(π/3-B).
设△ABC的内角A,B,C的对应边分别为a,b,c.已知角A.cos2B-cos2A=2sin(π/3+B)sin(π/3-B).(1)求角A的大小.
(2)试确定满足条件a=2√2,b=3的△ABC的个数.